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3x^2+5x-7=14.4
We move all terms to the left:
3x^2+5x-7-(14.4)=0
We add all the numbers together, and all the variables
3x^2+5x-21.4=0
a = 3; b = 5; c = -21.4;
Δ = b2-4ac
Δ = 52-4·3·(-21.4)
Δ = 281.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{281.8}}{2*3}=\frac{-5-\sqrt{281.8}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{281.8}}{2*3}=\frac{-5+\sqrt{281.8}}{6} $
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